next up previous
Next: Review for Second Exam Up: Calculus II Reviews and Previous: Calculus II Reviews and

First Exam

  1. $ \displaystyle{
\int x \cos (x^{2} + 1) \, d x
}
$
  2. $ \displaystyle{
\int x^{2} (x^{3} - 3)^{8} \, d x
}
$
  3. $ \displaystyle{
\int \frac{1}{\sqrt{4-x}} \, d x
}
$
  4. $ \displaystyle{
\int \sin \theta \cos^{6} \theta \, d \theta
}
$
  5. $ \displaystyle{
\int_{1}^{4} x e^{5x} \, d x
}
$
  6. $ \displaystyle{
\int x^{3} \ln x \, d x
}
$
  7. $ \displaystyle{
\int \frac{x+1}{6x + x^{2}} \, d x
}
$
  8. $ \displaystyle{
\int \frac{x^{4} + 3 x^{3} + 2 x^{2} + 1}{x^{2} + 3 x + 2} \, dx
}
$
  9. $ \displaystyle{
\int \frac{1}{x^{2} + 4 x + 5} \, d x
}
$
  10. $ \displaystyle{
\int_{1}^{5} \frac{dx}{x^{3/2}}
}
$
  11. $ \displaystyle{
\int (x+ \sin x)^{3} (1 + \cos x) \, dx
}
$
  12. $ \displaystyle{
\int \sin 3 x \, \sin 5 x \, dx
}
$
    Hint: $ \sin A \, \sin B = \frac{1}{2} [\cos (A-B) - \cos (A+B)]$
  13. $ \displaystyle{
\int \frac{x^{3}}{\sqrt{x^{2} + 9}} d x
}
$
    Hint: let $ x=3 \tan \theta$ .



lagcc 2005-01-03